グラフアプリその1
グラフを扱えれば色々便利だと思い作成
完成して走らせるとエラーが発生した
その時のコードが以下の通り
import PySimpleGUI as sg import matplotlib from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg from matplotlib.pyplot import axes, figure def update_figure(data): axes = fig.axes x = [i[0] for i in data] y = [int(i[1]) for i in data] axes[0].plot(x,y, 'r-') figure_canvas_agg.draw() figure_canvas_agg.get_tk_widget().pack() table_content = [] layout = [ [sg.Table( headings= ['Observation', 'Result'], values= table_content, expand_x=True, hide_vertical_scroll= True, key='-TABLE-')], [sg.Input(key= '-INPUT-', expand_x = True), sg.Button('Submit')], [sg.Canvas(key= '-CANVAS-')] ] window = sg.Window('グラフアプリ', layout, finalize=True) #matplotlib fig = matplotlib.figure.Figure(figsize= (5,4)) fig.add_subplot(111).plot([],[]) figure_canvas_agg= FigureCanvasTkAgg(fig,window['-CANVAS-'].TKCanvas) figure_canvas_agg.draw() figure_canvas_agg.get_tk_widget().pack() while True: event, values = window.read() if event == sg.WIN_CLOSED: break if event =='Submit': new_value = values['-INPUT-'] if new_value.isnumeric(): table_content.append([len(table_content) + 1, float(new_value)]) window['-TABLE-'].update(table_content) window['-INPUT-'].update('') update_figure(table_content) window.close()
まずはエラー内容の確認から解決していく
次回はエラー内容の把握する事から